(D) According to the de-Broglie equation: $\lambda = \frac{h}{mv}$.Given that the wavelength $(\lambda)$ is equal to the distance travelled by the ele

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(D) According to the de-Broglie equation: $\lambda = \frac{h}{mv}$.Given that the wavelength $(\lambda)$ is equal to the distance travelled by the electron in one second,we have $\lambda = v \times 1 = v$.Substituting $\lambda = v$ into the de-Broglie equation: $v = \frac{h}{mv}$.Rearranging the terms: $v^2 = \frac{h}{m}$,which gives $v = \sqrt{\frac{h}{m}}$.Since $\lambda = v$,we get $\lambda = \sqrt{\frac{h}{m}}$.Thus,the correct relation is $\lambda = \sqrt{\frac{h}{m}}$.

Class 11 Chemistry Structure of Atom De Broglie's principle

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Which of the following relations is correct,if the wavelength $(\lambda)$ is equal to the distance travelled by the electron in one second? $h$ is the Planck's constant and $m$ is the mass of electron.

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A
$\lambda = h / p$
B
$\lambda = h / m$
C
$\lambda = \sqrt{ h / p }$
D
$\lambda = \sqrt{ h / m }$

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Which of the following relations is correct,if the wavelength $(\lambda)$ is equal to the distance travelled by the electron in one second? $h$ is the Planck's constant and $m$ is the mass of electron.

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Find the $\%$ difference (approximate) in de Broglie wavelength if the temperature of a gas becomes double.

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