Which of the following reactions of glucose c | vedclass

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(C) The open-chain structure of glucose contains a free aldehyde group $(-CHO)$,which reacts with hydroxylamine $(NH_2OH)$ to form an oxime.However,th

Vedclass · Accepted Answer

Pentaacetate of glucose does not react with hydroxylamine.

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(C) The open-chain structure of glucose contains a free aldehyde group $(-CHO)$,which reacts with hydroxylamine $(NH_2OH)$ to form an oxime.However,the pentaacetate of glucose does not contain a free aldehyde group because the hemiacetal hydroxyl group at $C_1$ is involved in the formation of the cyclic structure and is subsequently acetylated.Since the cyclic structure is stable and the aldehyde group is masked in the hemiacetal form,the pentaacetate cannot react with hydroxylamine.This specific observation confirms the existence of the cyclic structure of glucose.

Which of the following reactions of glucose can be explained only by its cyclic structure?

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