Which of the following reactions is NOT given | vedclass

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(D) $(i)$ $SO_2$ (sulphur dioxide) reacts with potassium iodate to form sulphuric acid,potassium sulphate,and iodine gas: $5SO_2 + 2KIO_3 + 4H_2O \lon

Vedclass · Accepted Answer

It reacts with green-coloured ferrous sulphate to form yellowish-brown ferric sulphate.

Vedclass · Answer

(D) $(i)$ $SO_2$ (sulphur dioxide) reacts with potassium iodate to form sulphuric acid,potassium sulphate,and iodine gas: $5SO_2 + 2KIO_3 + 4H_2O \longrightarrow 4H_2SO_4 + K_2SO_4 + I_2$.$(ii)$ $SO_2$ decolourises acidified $KMnO_4$ solution by reducing $Mn^{7+}$ to $Mn^{2+}$: $5SO_2 + 2KMnO_4 + 2H_2O \longrightarrow K_2SO_4 + 2H_2SO_4 + 2MnSO_4$.$(iii)$ $SO_2$ reacts with acidified potassium dichromate $(K_2Cr_2O_7)$ to form green-coloured chromium$(III)$ sulphate: $3SO_2 + K_2Cr_2O_7 + H_2SO_4 \longrightarrow K_2SO_4 + Cr_2(SO_4)_3 + H_2O$.$(iv)$ $SO_2$ acts as a reducing agent and reduces ferric salts $(Fe^{3+})$ to ferrous salts $(Fe^{2+})$,changing the colour from yellow to light green: $Fe_2(SO_4)_3 + SO_2 + 2H_2O \longrightarrow 2FeSO_4 + 2H_2SO_4$. Therefore,the statement in option $D$ is incorrect as $SO_2$ reduces ferric sulphate to ferrous sulphate,not the other way around.

Which of the following reactions is $NOT$ given by $SO_2$?

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