(A) When sulphur is boiled with $NaOH$ solution,it undergoes a disproportionation reaction to form sodium thiosulphate and sodium sulphide.$4S + 6NaOH

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(A) When sulphur is boiled with $NaOH$ solution,it undergoes a disproportionation reaction to form sodium thiosulphate and sodium sulphide.$4S + 6NaOH \longrightarrow Na_2S_2O_3 + 2Na_2S + 3H_2O$

Class 12 Chemistry p-Block Elements (Class 12)Oxygen family

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Sulphur on boiling with $NaOH$ solution forms

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A
$Na_2S_2O_3 + Na_2S$
B
$Na_2SO_3 + SO_2$
C
$Na_2S_2O_3 + NaHSO_3$
D
$Na_2SO_3 + H_2S$

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p-Block Elements (Class 12)

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Oxygen family

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Why is dioxygen a gas but sulphur a solid?

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When sulphur is boiled with $Na_2SO_3$ solution,the compound formed is

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Match the following items of List-$I$ with those in List-$II$ and choose the correct option.
List-$I$ List-$II$
$(a) \ [S_2 O_3]^{2-}$ $(I)$ Paramagnetic
$(b) \ H_2 O_2$ $(II)$ Toxic gas
$(c) \ H_2 S$ $(III)$ Strong reducing agent
$(d) \ S_2$ $(IV)$ Disproportionate in presence of $Mn^{2+}$

List-$I$	List-$II$
$(a) \ [S_2 O_3]^{2-}$	$(I)$ Paramagnetic
$(b) \ H_2 O_2$	$(II)$ Toxic gas
$(c) \ H_2 S$	$(III)$ Strong reducing agent
$(d) \ S_2$	$(IV)$ Disproportionate in presence of $Mn^{2+}$

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