Which of the following reactions will not produce $CO_2$?

  • A
    $CH_3-CH_2-SO_3H \xrightarrow{NaHCO_3}$
  • B
    Malonic acid $\xrightarrow{\Delta}$
  • C
    $CH_3-CH_2-COONa \xrightarrow{\text{Electrolysis}}$
  • D
    $\beta$-keto acid $\xrightarrow{\Delta}$

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The decreasing order of the rate of alkaline hydrolysis for the following esters is:
$I: C_6H_5COOC_2H_5$
$II: p-Cl-C_6H_4COOC_2H_5$
$III: p-NO_2-C_6H_4COOC_2H_5$
$IV: p-CH_3O-C_6H_4COOC_2H_5$

The product $(C)$ of the following reaction is:

Arrange these carboxylic acids in decreasing order of ease of esterification with $CH_3OH/H^{+}$:
$(I)$ $CH_3-CH(CH_3)-COOH$
$(II)$ $CH_3-CH(CH_3)-CH_2-COOH$
$(III)$ $CH_3-C(CH_3)_2-COOH$
$(IV)$ $(CH_3-CH_2)_3C-COOH$

The silver salt of a fatty acid on refluxing with an alkyl halide gives an

In the given reaction :
$CH_3-COOH$ $\mathop{\xrightarrow{(i) Br_2/P}}_{(ii) NaCN, (iii) H_2O/H^{+}/\Delta}$ $[X]$
$[X]$ will be :

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