The product (C) of the following reaction is: | vedclass

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(A) $1$. The starting material is ethylbenzene. Nitration with $HNO_3/H_2SO_4$ introduces two nitro groups at the ortho and para positions relative to

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$2,4-$dinitrobenzoyl chloride

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(A) $1$. The starting material is ethylbenzene. Nitration with $HNO_3/H_2SO_4$ introduces two nitro groups at the ortho and para positions relative to the ethyl group,forming $1-$ethyl$-2,4-$dinitrobenzene $(A)$.$2$. Oxidation of the alkyl side chain with $KMnO_4/\Delta$ converts the ethyl group into a carboxylic acid group,resulting in $2,4-$dinitrobenzoic acid $(B)$.$3$. Treatment of the carboxylic acid with $SOCl_2$ converts the $-COOH$ group into an acid chloride group $(-COCl)$,yielding $2,4-$dinitrobenzoyl chloride $(C)$.

The product $(C)$ of the following reaction is:

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