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(C) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} 	ext{ BM}$,where $n$ is the number of unpaired electrons.
$Cr^{

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$Cr^{2+}$ and $Fe^{2+}$

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(C) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} 	ext{ BM}$,where $n$ is the number of unpaired electrons.
$Cr^{2+} (Z=24): [Ar] 3d^4$. Number of unpaired electrons $(n) = 4$.
$Fe^{2+} (Z=26): [Ar] 3d^6$. Number of unpaired electrons $(n) = 4$.
Since both $Cr^{2+}$ and $Fe^{2+}$ have $4$ unpaired electrons,they have the same calculated value of magnetic moment.

Which of the following pairs of transition metal ions have the same calculated values of magnetic moment?

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