In the circuit shown in the figure below, whi | vedclass

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Question

(A) The circuit consists of two batteries of $10\, V$ and $20\, V$ in series, and total resistance $R_{eq} = 7.5\, \Omega + 0.5\, \Omega + 1\, \Omega

Vedclass · Accepted Answer

The potential at $P$ is $-7.5\, V$

Vedclass · Answer

(A) The circuit consists of two batteries of $10\, V$ and $20\, V$ in series, and total resistance $R_{eq} = 7.5\, \Omega + 0.5\, \Omega + 1\, \Omega + 1\, \Omega = 10\, \Omega$. The net electromotive force is $\varepsilon_{net} = 20\, V - 10\, V = 10\, V$. The current in the circuit is $I = \frac{\varepsilon_{net}}{R_{eq}} = \frac{10\, V}{10\, \Omega} = 1\, A$, flowing in the direction of the $20\, V$ battery. Since the point $G$ is grounded, $V_G = 0\, V$, so $V_S = 0\, V$ and $V_R = 0\, V$. Moving from $R$ to $Q$ through the $1\, \Omega$ resistor against the current, $V_Q = V_R + I 	imes 1\, \Omega = 0 + 1\, A 	imes 1\, \Omega = 1\, V$. Moving from $Q$ to $P$ through the batteries and internal resistance, $V_P = V_Q + 20\, V - 1\, \Omega 	imes 1\, A - 10\, V - 0.5\, \Omega 	imes 1\, A = 1 + 20 - 1 - 10 - 0.5 = 9.5\, V$. Re-evaluating the options based on the circuit diagram: $V_S = 0\, V$ and $V_R = 0\, V$ are correct. $V_Q = 1\, V$ is correct. Option $A$ is incorrect as $V_P$ is not $-7.5\, V$.

In the circuit shown in the figure below, which of the following statements is incorrect?

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