Which of the following pairs does not consist | vedclass

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(D) Isoelectronic species are those that have the same number of electrons.$1. Sm^{2+}: 62 - 2 = 60 	ext{ electrons}; Er^{3+}: 68 - 3 = 65 	ext{ ele

Vedclass · Accepted Answer

Both $(A)$ and $(C)$ are correct

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(D) Isoelectronic species are those that have the same number of electrons.$1. Sm^{2+}: 62 - 2 = 60 	ext{ electrons}; Er^{3+}: 68 - 3 = 65 	ext{ electrons}$. Since $60 
eq 65$,they are not isoelectronic.$2. Yb^{2+}: 70 - 2 = 68 	ext{ electrons}; Lu^{3+}: 71 - 3 = 68 	ext{ electrons}$. Since $68 = 68$,they are isoelectronic.$3. Tb^{2+}: 65 - 2 = 63 	ext{ electrons}; Tm^{4+}: 69 - 4 = 65 	ext{ electrons}$. Since $63 
eq 65$,they are not isoelectronic.Therefore,both pairs $(A)$ and $(C)$ are not isoelectronic.

Which of the following pairs does not consist of isoelectronic species? (Atomic numbers: $Sm = 62, Er = 68, Yb = 70, Lu = 71, Eu = 63, Tb = 65, Tm = 69$)

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