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(A) The basic strength of metallic hydroxides depends on the ionic character of the $M-OH$ bond.As the size of the metal cation increases,the ionic ch

Vedclass · Accepted Answer

$Al(OH)_3 < Lu(OH)_3 < Ce(OH)_3 < Ca(OH)_2$

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(A) The basic strength of metallic hydroxides depends on the ionic character of the $M-OH$ bond.As the size of the metal cation increases,the ionic character of the $M-OH$ bond increases,leading to higher basicity.$Al(OH)_3$ is amphoteric and is the least basic among the given compounds.Among the lanthanoids,the basic strength decreases as the ionic radius decreases due to lanthanoid contraction $(Ce^{3+} > Lu^{3+})$.$Ca(OH)_2$ is a strong base compared to the lanthanoid hydroxides.Therefore,the correct order of increasing basic strength is $Al(OH)_3 < Lu(OH)_3 < Ce(OH)_3 < Ca(OH)_2$.

Which of the following options represents the correct order of basic strength for the given metallic hydroxides?

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