Calculate the 'spin only' magnetic moment of $M ^{2+}(\operatorname{aq})$ ion $(Z=27)$
Calculate the 'spin only' magnetic moment of $M ^{2+}(\operatorname{aq})$ ion $(Z=27)$
$Z=27$
$\Rightarrow[ Ar ] 3 d^{7} 4 s^{2}$
$\therefore M^{2+}=[A r] 3 d^{7}$
i.e., $3$ unpaired electrons
$\therefore n=3$
$\Rightarrow \sqrt{n(n+2)}=\mu$
$\Rightarrow \sqrt{3(3+2)}=\mu$
$\Rightarrow \sqrt{15}=\mu$
$\mu \approx 4 \,BM$
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