Which of the following molecules represents the order of hybridisation $sp^2, sp^2, sp, sp$ from left to right for the carbon atoms?

  • A
    $HC \equiv C-C \equiv CH$
  • B
    $CH_{2}=CH-C \equiv CH$
  • C
    $CH_{2}=CH-CH=CH_{2}$
  • D
    $CH_{3}-CH=CH-CH_{3}$

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Similar Questions

What hybrid orbitals are present in the following compound $H_3C - CH = CH - CH_2 - CH_3$?

Amongst the given options,the compound$(s)$ in which all the atoms are in one plane in all the possible conformations (if any),is (are):
$(A)$ $CH_2=CH-CH=CH_2$
$(B)$ $HC\equiv C-CH=CH_2$
$(C)$ $H_2C=C=O$
$(D)$ $H_2C=C=CH_2$

Match the following lists:
List-$I$List-$II$
$A$. Ethane$1$. $2 \ sp$ carbons
$B$. Ethylene$2$. $6 \ sp^2$ carbons
$C$. Acetylene$3$. $2 \ sp^3$ carbons
$D$. Benzene$4$. $2 \ sp^2$ carbons
$5$. $1 \ sp$ and $1 \ sp^2$ carbons

What is the type of hybridisation of each carbon atom in the following compounds?
$(a)$ $CH_{3}Cl$
$(b)$ $(CH_{3})_{2}CO$
$(c)$ $CH_{3}CN$
$(d)$ $HCONH_{2}$
$(e)$ $CH_{3}CH=CHCN$

Which among the following possesses a $sp$ carbon in its structure?

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