Which of the following molecules contains the | vedclass

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(D) To determine the number of electrons in antibonding molecular orbitals,we write the molecular orbital configuration for each molecule:$1$. $Li_2$

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$F_2$

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(D) To determine the number of electrons in antibonding molecular orbitals,we write the molecular orbital configuration for each molecule:$1$. $Li_2$ ($6$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2$. Antibonding electrons = $2$ (in $\sigma^* 1s$).$2$. $N_2$ ($14$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2, \sigma 2p_z^2$. Antibonding electrons = $2+2 = 4$.$3$. $O_2$ ($16$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1 = \pi^* 2p_y^1$. Antibonding electrons = $2+2+2 = 6$.$4$. $F_2$ ($18$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$. Antibonding electrons = $2+2+4 = 8$.Thus,$F_2$ contains the maximum number of electrons in antibonding molecular orbitals.

Column $I$	Column $II$
$(A)$ $B_2$	$(p)$ Paramagnetic
$(B)$ $N_2$	$(q)$ Undergoes oxidation
$(C)$ $O_2^{-}$	$(r)$ Undergoes reduction
$(D)$ $O_2$	$(s)$ Bond order $\geq 2$
	$(t)$ Mixing of '$s$' and '$p$' orbitals

Which of the following molecules contains the maximum number of electrons in antibonding molecular orbitals?

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