Which of the following magnetic moment values | vedclass

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Question

$\mu=\sqrt{n(n+2)} \,\,B M$

$\mu=2 \sqrt{2}$ i.e. $=$ unpaired $\mathrm{e}^{-}=2=\mathrm{Mn}^{+5}$

$\mu=\sqrt{15}$ i.e. $=$ unpaired $\mathrm{e}

Vedclass · Accepted Answer

$2\sqrt 2 $

Vedclass · Answer

$\mu=\sqrt{n(n+2)} \,\,B M$

$\mu=2 \sqrt{2}$ i.e. $=$ unpaired $\mathrm{e}^{-}=2=\mathrm{Mn}^{+5}$

$\mu=\sqrt{15}$ i.e. $=$ unpaired $\mathrm{e}^{-}=3=\mathrm{Mn}^{+4}$

$\mu=\sqrt{35}$ i.e. $=$ unpaired $\mathrm{e}^{-}=5=\mathrm{Mn}^{+2}$

$\mu=\sqrt{24}$ i.e. $=$ unpaired $\mathrm{e}^{-}=4=\mathrm{Mn}^{+3}$

IE $\propto$ vecharge so $\mathrm{Mn}^{+5}$ have higher $IE$

Which of the following magnetic moment values will corresponds to highest ionization energy for $Mn$

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