Which of the following is the most stable car | vedclass

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(D) The stability of a carbocation is determined by the electronic effects of the substituents attached to the benzene ring.Electron-donating groups $

Vedclass · Accepted Answer

$p-CH_3O-C_6H_4-CH_2^+$

Vedclass · Answer

(D) The stability of a carbocation is determined by the electronic effects of the substituents attached to the benzene ring.Electron-donating groups $(EDG)$ increase the stability of a carbocation by donating electron density through resonance or inductive effects.Electron-withdrawing groups $(EWG)$ decrease the stability of a carbocation by withdrawing electron density.In the given options:$1$. $-NO_2$ is a strong $EWG$ ($-M$ and $-I$ effect).$2$. $-Cl$ is an $EWG$ ($-I$ effect,though it has $+M$ effect,the $-I$ effect dominates in this position).$3$. $-H$ is the reference (no effect).$4$. $-OCH_3$ is an $EDG$ ($+M$ effect).Since $-OCH_3$ is an electron-donating group,it stabilizes the positive charge on the benzylic carbon most effectively.Therefore,$p-CH_3O-C_6H_4-CH_2^+$ is the most stable carbocation.

Which of the following is the most stable carbocation?

Similar Questions

Arrange the $(C-H)$ bonds $x, y$ and $z$ in decreasing order of their bond dissociation energies in homolysis.

The decreasing order of stability of the following carbocations is:
$A$. $m-CH_3O-C_6H_4-CH_2^+$
$B$. $p-CH_3O-C_6H_4-CH_2^+$
$C$. $C_6H_5-CH_2^+$
$D$. $p-NO_2-C_6H_4-CH_2^+$

The correct order of stability of the following carbocations is:

Which of the following is an incorrect stability order?

The correct order of stability is:

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