Arrange the (C-H) bonds x, y and z in decreas | vedclass

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(B) The bond dissociation energy is inversely proportional to the stability of the free radical formed after homolysis.$1$. Homolysis of bond $z$ prod

Vedclass · Accepted Answer

$z > x > y$

Vedclass · Answer

(B) The bond dissociation energy is inversely proportional to the stability of the free radical formed after homolysis.$1$. Homolysis of bond $z$ produces a vinylic radical,which is highly unstable.$2$. Homolysis of bond $x$ produces an allylic radical,which is stabilized by hyperconjugation.$3$. Homolysis of bond $y$ produces a radical that is stabilized by both resonance and hyperconjugation.Since the stability of the radicals follows the order: $y > x > z$,the bond dissociation energies follow the reverse order: $z > x > y$.

Arrange the $(C-H)$ bonds $x, y$ and $z$ in decreasing order of their bond dissociation energies in homolysis.

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