Which of the following is the correct structu | vedclass

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(A) -Glucose has the configuration $OH$ on the right at $C-2, C-4, C-5$ and on the left at $C-3$. $L$-Glucose is the enantiomer of $D$-Glucose,meaning

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(A) -Glucose has the configuration $OH$ on the right at $C-2, C-4, C-5$ and on the left at $C-3$. $L$-Glucose is the enantiomer of $D$-Glucose,meaning all chiral centers have the opposite configuration. Therefore,in $L$-Glucose,the $OH$ groups are on the left at $C-2, C-4, C-5$ and on the right at $C-3$. The structure corresponding to this is shown in option $A$.

Which of the following is the correct structure of $L$-Glucose?

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