Which of the following is the correct increas | vedclass

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(A) $(1)$ For alkali metal bicarbonates,the solubility increases down the group due to the decrease in lattice energy being more significant than the

Vedclass · Accepted Answer

Solubility in $H_2O: NaHCO_3 < KHCO_3 < RbHCO_3 < CsHCO_3$

Vedclass · Answer

(A) $(1)$ For alkali metal bicarbonates,the solubility increases down the group due to the decrease in lattice energy being more significant than the decrease in hydration energy. Thus,$NaHCO_3 $(2)$ Boiling point order for group $15$ hydrides is $PH_3 $(3)$ According to Fajan's rule,as the charge on the cation increases,polarization increases,which increases the covalent character and decreases the ionic character. Thus,$Fe_2O_3$ has more covalent character than $FeO$.$(4)$ $IE_2$ of $Na$ $([Ne] 3s^1)$ is very high because the second electron is removed from a stable noble gas configuration,whereas $Mg$ $([Ne] 3s^2)$ has a lower $IE_2$ as it achieves a stable configuration after removing one electron. Thus,$Mg < Na$.

Which of the following is the correct increasing order for the mentioned property?

Similar Questions

In the given reaction,the oxide of sodium is .... $4Na + O_2 \to 2Na_2O$ and $Na_2O + H_2O \to 2NaOH$

Compound $A$ reacts with $NH_4Cl$ and forms a compound $B$. Compound $B$ reacts with $H_2O$ and excess of $CO_2$ to form compound $C$,which on reaction with saturated $NaCl$ solution forms sodium hydrogen carbonate. Compounds $A, B$ and $C$ are respectively:

Which of the following does not contain $Mg$:

Which of the following statements is $CORRECT$?

Consider the following reactions:
$Cs + O_2 \text{ (excess)} \rightarrow X$
$Na + O_2 \rightarrow Y$
Identify the correct statement about $X$ and $Y$.

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