Which of the following statements is correct?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. Linkage isomerism is shown by ligands that have two donor atoms (ambidentate ligands). In $[Pt(NO_3)_2(en)_2]^{2+}$,the $NO_3^-$ ligand is no

Vedclass · Accepted Answer

$FeCl_3 \cdot 6H_2O$ can show hydrate isomerism

Vedclass · Answer

(C) $1$. Linkage isomerism is shown by ligands that have two donor atoms (ambidentate ligands). In $[Pt(NO_3)_2(en)_2]^{2+}$,the $NO_3^-$ ligand is not ambidentate,so it does not show linkage isomerism.$2$. Ionization isomerism occurs when the counter ion in the coordination sphere is a potential ligand and can displace a ligand in the coordination sphere. In $[Cr(CO_3)(NH_3)_4]Br$,the $Br^-$ ion can exchange with the $CO_3^{2-}$ ion,thus exhibiting ionization isomerism.$3$. Hydrate isomerism occurs when water molecules act as ligands or as free molecules of hydration. $FeCl_3 \cdot 6H_2O$ can exist as $[Fe(H_2O)_6]Cl_3$,$[Fe(H_2O)_5Cl]Cl_2 \cdot H_2O$,etc.,thus it shows hydrate isomerism.$4$. $[FeCl_3(NH_3)_3]$ exhibits geometrical isomerism (facial and meridional),which is a type of stereoisomerism,not structural isomerism.$5$. Both $B$ and $C$ are technically correct statements in the context of coordination chemistry. However,$FeCl_3 \cdot 6H_2O$ is the classic textbook example for hydrate isomerism.

Similar Questions

If $\overline{a}, \overline{b}, \overline{c}$ are non-coplanar unit vectors such that $\overline{a} \times (\overline{b} \times \overline{c}) = \frac{\overline{b} + \overline{c}}{\sqrt{2}}$,then the angle between $\overline{a}$ and $\overline{b}$ is

Variable number of tandem repeats $(VNTRs)$ in the $DNA$ molecule are highly useful in:

Product $(A)$ is

The number of ways of choosing $10$ objects out of $31$ objects,of which $10$ are identical and the remaining $21$ are distinct,is

If $\int \frac{e^x-1}{e^x+1} d x=f(x)+c$,then $f(x)$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module