Which of the following is not true about vect | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The dot product (scalar product) of two vectors results in a scalar,while the cross product (vector product) results in a vector.$1$. For $(\vec{A

Vedclass · Accepted Answer

$(\vec{A} 	imes \vec{C}) 	imes(\vec{B} 	imes \vec{C})$ is a scalar value.

Vedclass · Answer

(C) The dot product (scalar product) of two vectors results in a scalar,while the cross product (vector product) results in a vector.$1$. For $(\vec{A} \cdot \vec{A})(\vec{B} \cdot \vec{C})$: Both $(\vec{A} \cdot \vec{A})$ and $(\vec{B} \cdot \vec{C})$ are scalars. The product of two scalars is a scalar. This statement is true.$2$. For $(\vec{A} 	imes \vec{B}) \cdot(\vec{B} 	imes \vec{C})$: Both $(\vec{A} 	imes \vec{B})$ and $(\vec{B} 	imes \vec{C})$ are vectors. The dot product of two vectors is a scalar. This statement is true.$3$. For $(\vec{A} 	imes \vec{C}) 	imes(\vec{B} 	imes \vec{C})$: Both $(\vec{A} 	imes \vec{C})$ and $(\vec{B} 	imes \vec{C})$ are vectors. The cross product of two vectors is a vector. Therefore,the statement that it is a scalar value is false.$4$. For $\vec{A} 	imes(\vec{B} 	imes \vec{C})$: $(\vec{B} 	imes \vec{C})$ is a vector. The cross product of $\vec{A}$ with this vector results in another vector. This statement is true.

Which of the following is not true about vectors $\vec{A}, \vec{B}$ and $\vec{C}$?

Similar Questions

If for two vectors $\vec{A}$ and $\vec{B}$,$\vec{A} \times \vec{B} = 0$,then the vectors:

The vectors from the origin to the points $A$ and $B$ are $\overrightarrow A = 3\hat i - 6\hat j + 2\hat k$ and $\overrightarrow B = 2\hat i + \hat j - 2\hat k$ respectively. The area of the triangle $OAB$ is:

The angle between the vectors $(\hat{i} + \hat{j})$ and $(\hat{i} - \hat{k})$ is ........ $^\circ$.

The angle between $(\overrightarrow{A} - \overrightarrow{B})$ and $(\overrightarrow{A} \times \overrightarrow{B})$ is $(\overrightarrow{A} \neq \overrightarrow{B})$. (in $^{\circ}$)

Let $\vec A = (\hat i + \hat j)$ and $\vec B = (2\hat i - \hat j)$. The magnitude of a coplanar vector $\vec C$ such that $\vec A \cdot \vec C = \vec B \cdot \vec C = \vec A \cdot \vec B$ is given by

Vedclass Test Series

Exam Paper Generator

Online Exam Module