Which of the following is a weak field ligand | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the spectrochemical series,ligands are arranged in increasing order of their field strength:
$I^{-} < Br^{-} < S^{2-} < SCN

Vedclass · Accepted Answer

$F^{-}$

Vedclass · Answer

(C) According to the spectrochemical series,ligands are arranged in increasing order of their field strength:
$I^{-} < Br^{-} < S^{2-} < SCN^{-} < Cl^{-} < F^{-} < OH^{-} < H_2O < NCS^{-} < EDTA^{4-} < NH_3 < en < CN^{-} < CO$.
Ligands like $F^{-}$,$Cl^{-}$,$Br^{-}$,and $I^{-}$ are considered weak field ligands because they cause small crystal field splitting $(\Delta_o)$.
Among the given options,$F^{-}$ is a weak field ligand,while $EDTA^{4-}$,$NH_3$,and $CO$ are strong field ligands.

Which of the following is a weak field ligand?

Similar Questions

Which one of the following complexes will have $\Delta_0 = 0$ and $\mu = 5.96 \ B.M.?$

$[Pd(F)(Cl)(Br)(I)]^{2-}$ has $n$ number of geometrical isomers. Then,the spin-only magnetic moment and crystal field stabilisation energy $[CFSE]$ of $[Fe(CN)_6]^{n-6}$ are
[Note : Ignore the pairing energy]

Explain crystal field splitting in tetrahedral complexes.

How is the $t_{2g}^4 e_g^0$ configuration possible for a $d^4$ ion during crystal field splitting in an octahedral complex?

An ion $M^{2+}$ forms the complexes $[M(H_2O)_6]^{2+}$,$[M(en)_3]^{2+}$,and $[MBr_6]^{4-}$. Match the complex with the appropriate colour.

Vedclass Test Series

Exam Paper Generator

Online Exam Module