Which of the following is an E isomer? | vedclass

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(C) To determine the $E$ isomer,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules. $1$. Assign priorities to the groups attached to each carbon of

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(C) To determine the $E$ isomer,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules. $1$. Assign priorities to the groups attached to each carbon of the double bond based on atomic number. $2$. If the groups with higher priority are on opposite sides of the double bond,it is an $E$ (entgegen) isomer. $3$. In option $C$,for the left carbon,$F$ (atomic number $9$) has higher priority than $CH_2I_3$ (atomic number $6$). For the right carbon,$NMe_2$ (nitrogen atomic number $7$) has higher priority than $OMe$ (oxygen atomic number $8$). Wait,checking priorities: Oxygen $(8)$ > Nitrogen $(7)$. So $OMe$ > $NMe_2$. $4$. In option $C$,the higher priority groups are $F$ and $OMe$. They are on opposite sides,making it the $E$ isomer.

Which of the following is an $E$ isomer?

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