Which of the following compounds has an E-con | vedclass

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(B) To determine the $E/Z$ configuration,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules based on atomic number.$1$. For option $A$: The groups o

Vedclass · Accepted Answer

$BrCH_2-C(CH_3)=C(CH_3)-C_2H_5$

Vedclass · Answer

(B) To determine the $E/Z$ configuration,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules based on atomic number.$1$. For option $A$: The groups on the left carbon are $-CH_3$ and $-H$ (priority: $-CH_3 > -H$). The groups on the right carbon are $-C_2H_5$ and $-H$ (priority: $-C_2H_5 > -H$). Since the higher priority groups are on the same side,it is $Z$-but$-2-$ene.$2$. For option $B$: The left carbon has $-BrCH_2$ and $-CH_3$ (priority: $-BrCH_2 > -CH_3$). The right carbon has $-CH_3$ and $-C_2H_5$ (priority: $-C_2H_5 > -CH_3$). The higher priority groups are on opposite sides,thus it is $E$.$3$. For option $C$: The left carbon has $-Br$ and $-HOCH_2$ (priority: $-Br > -HOCH_2$). The right carbon has $-CH(CH_3)_2$ and $-CH_2CH_3$ (priority: $-CH(CH_3)_2 > -CH_2CH_3$). The higher priority groups are on the same side,thus it is $Z$.$4$. For option $D$: The left carbon has $-Br$ and $-Cl$ (priority: $-Br > -Cl$). The right carbon has $-D$ and $-H$ (priority: $-D > -H$). The higher priority groups are on the same side,thus it is $Z$.Therefore,option $B$ represents the $E$-configuration.

Which of the following compounds has an $E$-configuration?

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