Which of the following graphs is the graph of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The function $f(x) = 	an^{-1} x$ is defined for all real numbers $x \in R$.Its range is the open interval $(-\frac{\pi}{2}, \frac{\pi}{2})$.The g

Vedclass · Accepted Answer

Vedclass · Answer

(C) The function $f(x) = 	an^{-1} x$ is defined for all real numbers $x \in R$.Its range is the open interval $(-\frac{\pi}{2}, \frac{\pi}{2})$.The graph passes through the origin $(0, 0)$ because $	an^{-1}(0) = 0$.As $x 	o \infty$,$f(x) 	o \frac{\pi}{2}$,and as $x 	o -\infty$,$f(x) 	o -\frac{\pi}{2}$.The graph is strictly increasing and has horizontal asymptotes at $y = \frac{\pi}{2}$ and $y = -\frac{\pi}{2}$.Comparing this with the given options,the graph in option $C$ correctly represents the function $f(x) = 	an^{-1} x$.

Which of the following graphs is the graph of $f(x) = \tan^{-1} x, (x \in R)$?

Similar Questions

$\coth^{-1}(2) + \operatorname{cosech}^{-1}(-2\sqrt{2}) = $

$2 \tanh^{-1} \frac{1}{2}$ is equal to

Let $a, b$ and $c$ be the lengths of the sides of a triangle with its opposite angles $A, B$ and $C$ respectively. If $a=3, b=4$ and $A=\sin^{-1}\left(\frac{3}{4}\right)$,then the angle $B$ is (in $^{\circ}$)

$\tan ^{-1}\left(\tan \frac{31 \pi}{6}\right)=$ . . . . . . .

$\sin^{-1}(\sin \frac{7\pi}{6}) = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module