(N/A) In the given figure,we have a parallelogram $ABCD$ and a trapezium $ABST$.
For figures to lie on the same base and between the same parallels,they must share a common side as a base,and their remaining vertices must lie on a line parallel to that base.
Here,the parallelogram $ABCD$ and the trapezium $ABST$ share the common base $AB$.
However,the vertices $D$ and $C$ of the parallelogram lie on the line $DC$,while the vertices $T$ and $S$ of the trapezium lie on the line $TS$.
Since the line $DC$ is not the same as the line $TS$,the two figures do not lie between the same parallels.
Therefore,the answer is negative.