Which of the following expressions is correct | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a $CsCl$ crystal structure,$Cl^{-}$ ions are located at the corners of a simple cubic unit cell,and the $Cs^{+}$ ion is located at the body cen

Vedclass · Accepted Answer

$r_c + r_a = \frac{\sqrt{3} a}{2}$

Vedclass · Answer

(C) In a $CsCl$ crystal structure,$Cl^{-}$ ions are located at the corners of a simple cubic unit cell,and the $Cs^{+}$ ion is located at the body center.Along the body diagonal,the $Cs^{+}$ ion and the $Cl^{-}$ ions at the corners touch each other.The length of the body diagonal is given by $\sqrt{3} a$.Since the body diagonal consists of two $Cl^{-}$ radii and one $Cs^{+}$ diameter (two $Cs^{+}$ radii),we have:$2 r_c + 2 r_a = \sqrt{3} a$Dividing by $2$,we get:$r_c + r_a = \frac{\sqrt{3} a}{2}$

Which of the following expressions is correct in the case of a $CsCl$ unit cell (edge length,$a$)?

Similar Questions

The density of the unit cell of $Li$ is $0.539 \ g/cm^3$ and the edge length of the unit cell is $3.5 \ \mathring{A}$. How many $Li$ atoms are present in a unit cell of lithium? (Atomic mass of $Li = 6.94 \ g/mol$)

Calculate the number of atoms in $5 \ g$ of a metal that crystallises in a simple cubic unit cell structure with an edge length of $336 \ pm$. (Density of the metal $= 9.4 \ g \ cm^{-3}$)

Lithium has a $bcc$ structure. Its density is $530 \ kg \ m^{-3}$ and its atomic mass is $6.94 \ g \ mol^{-1}$. Calculate the edge length of a unit cell of lithium metal in $pm$ $(N_A = 6.02 \times 10^{23} \ mol^{-1})$.

In a face-centered cubic $(FCC)$ unit cell, if the edge length is $508 \text{ pm}$, what is the radius of the atom in $\text{pm}$?

Select the $INCORRECT$ option regarding the cubic crystal system-

Vedclass Test Series

Exam Paper Generator

Online Exam Module