Which of the following molecules does not exi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Molecular Orbital Theory,the bond order is calculated as: $Bond \ Order = \frac{1}{2} (N_b - N_a)$,where $N_b$ is the number of elect

Vedclass · Accepted Answer

$He_2$

Vedclass · Answer

(C) According to Molecular Orbital Theory,the bond order is calculated as: $Bond \ Order = \frac{1}{2} (N_b - N_a)$,where $N_b$ is the number of electrons in bonding orbitals and $N_a$ is the number of electrons in antibonding orbitals.For $He_2$,the electronic configuration is $\sigma 1s^2, \sigma^* 1s^2$.Bond order = $\frac{1}{2} (2 - 2) = 0$.Since the bond order is $0$,the molecule $He_2$ does not exist.

Which of the following molecules does not exist on the basis of Molecular Orbital Theory?

Similar Questions

Explain the difference between positive (bonding) and negative (antibonding) overlapping of orbitals.

For a stable molecule,the value of bond order must be

Which of the following electronic configurations is correct for the given species?

Which of the following molecular orbitals has a nodal plane and is relatively higher in energy compared to bonding orbitals?

How do you express the bond strength in terms of bond order?

Vedclass Test Series

Exam Paper Generator

Online Exam Module