The species A,B,C,D formed in the following b | vedclass

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Question

(A) In the first reaction,$CH_3CH_2-I \rightarrow A + B$,the bond breaks heterolytically such that the bonding electron pair moves to the more electro

Vedclass · Accepted Answer

$CH_3CH_2^{+}, I^{-}, CH_3CH_2^{-}, Cu^{+}$

Vedclass · Answer

(A) In the first reaction,$CH_3CH_2-I \rightarrow A + B$,the bond breaks heterolytically such that the bonding electron pair moves to the more electronegative iodine atom. This results in the formation of an ethyl carbocation $(A = CH_3CH_2^{+})$ and an iodide ion $(B = I^{-})$.In the second reaction,$CH_3CH_2-Cu \rightarrow C + D$,the bond breaks heterolytically such that the bonding electron pair moves to the carbon atom because carbon is more electronegative than copper. This results in the formation of an ethyl carbanion $(C = CH_3CH_2^{-})$ and a copper cation $(D = Cu^{+})$.

The species $A$,$B$,$C$,$D$ formed in the following bond cleavages respectively are:

Similar Questions

$A$ migration of hydrogen with a pair of electrons is called

How many $1,2-$ shifts take place in the following carbocation to reach the most stable form?

The stability of carbanions follows the order:
$I: CH_3CH_2CH_2\bar{C}H_2$
$II: CH_3\bar{C}HCH_2CH_3$
$III: (CH_3)_3\bar{C}$
$IV: CH_3\bar{C}(Ph)CH_2CH_3$

Which of the following options given below is incorrect?

What is homolytic cleavage of a covalent bond? Explain with an example. Or,write about bond cleavage and the intermediate free radical.

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