Which of the following compounds exhibits the | vedclass

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(C) To find the oxidation state of carbon in each compound,we use the rule that the sum of oxidation states of all atoms in a neutral molecule is $0$.

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$CHCl_3$

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(C) To find the oxidation state of carbon in each compound,we use the rule that the sum of oxidation states of all atoms in a neutral molecule is $0$. Let the oxidation state of carbon be $x$.$1$. In $HCHO$: $2(+1) + x + (-2) = 0 \implies x = 0$.$2$. In $CH_3OH$: $x + 3(+1) + (-2) + (+1) = 0 \implies x + 2 = 0 \implies x = -2$.$3$. In $CHCl_3$: $x + 1(+1) + 3(-1) = 0 \implies x - 2 = 0 \implies x = +2$.$4$. In $C_{12}H_{22}O_{11}$ (Sucrose): $12x + 22(+1) + 11(-2) = 0 \implies 12x + 22 - 22 = 0 \implies 12x = 0 \implies x = 0$.Comparing the values $(0, -2, +2, 0)$,the maximum oxidation state is $+2$ in $CHCl_3$.

Which of the following compounds exhibits the maximum oxidation state of carbon?

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