Which of the following complexes formed by Ni | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the spectrochemical series,$CN^-$ and $CO$ are strong field ligands,while $Cl^-$ is a weak field ligand. $Ni^{2+}$ $(3d^8)$ with four

Vedclass · Accepted Answer

$[Ni(Cl)_4]^{2-}$

Vedclass · Answer

(C) According to the spectrochemical series,$CN^-$ and $CO$ are strong field ligands,while $Cl^-$ is a weak field ligand. $Ni^{2+}$ $(3d^8)$ with four strong field ligands forms a square planar,diamagnetic complex like $[Ni(CN)_4]^{2-}$. $Ni(0)$ $(3d^8 4s^2)$ with four strong field ligands forms a tetrahedral,diamagnetic complex like $[Ni(CO)_4]$. $Ni^{2+}$ $(3d^8)$ with four weak field ligands $(Cl^-)$ forms a tetrahedral,paramagnetic complex $[Ni(Cl)_4]^{2-}$. In $[Ni(Cl)_4]^{2-}$,the $Ni^{2+}$ ion has an electronic configuration of $[Ar] 3d^8$. Due to the weak field ligand,no pairing occurs,resulting in two unpaired electrons in the $d$-orbitals,making it paramagnetic.

List-$I$	List-$II$
$(1)$ $dsp^2$	$(A)$ $BrF_5$
$(2)$ $sp^3d^2$	$(B)$ $[Co(NH_3)_6]^{3+}$
$(3)$ $sp^3d$	$(C)$ $[PtCl_4]^{2-}$
$(4)$ $d^2sp^3$	$(D)$ $PCl_5$

Which of the following complexes formed by $Nickel$ is tetrahedral and paramagnetic?

Similar Questions

In $[Cu(NH_3)_4]SO_4$,$Cu$ has the following hybridization:

Chromium hexacarbonyl,$Cr(CO)_6$,is an octahedral compound involving which type of hybridization?

Match the type of hybridization given in List-$I$ with the molecules/ions given in List-$II$.

List-$I$ List-$II$

$(1)$ $dsp^2$ $(A)$ $BrF_5$

$(2)$ $sp^3d^2$ $(B)$ $[Co(NH_3)_6]^{3+}$

$(3)$ $sp^3d$ $(C)$ $[PtCl_4]^{2-}$

$(4)$ $d^2sp^3$ $(D)$ $PCl_5$

In the formation of $K_4[Fe(CN)_6]$,the hybridisation involved is

Which of the following ions forms complexes with a coordination number of only $4$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module