Chromium hexacarbonyl,Cr(CO)_6,is an octahedr | vedclass

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(C) The central metal atom in $Cr(CO)_6$ is Chromium $(Cr)$.The atomic number of $Cr$ is $24$,and its electronic configuration is $[Ar] 3d^5 4s^1$.In

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$d^2sp^3$

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(C) The central metal atom in $Cr(CO)_6$ is Chromium $(Cr)$.The atomic number of $Cr$ is $24$,and its electronic configuration is $[Ar] 3d^5 4s^1$.In $Cr(CO)_6$,the oxidation state of $Cr$ is $0$ because $CO$ is a neutral ligand.$CO$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.The $3d$ orbitals become $t_{2g}^6 e_g^0$,leaving two $3d$ orbitals empty.These two $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals hybridize to form six $d^2sp^3$ hybrid orbitals.Thus,the hybridization is $d^2sp^3$ and the geometry is octahedral.

Chromium hexacarbonyl,$Cr(CO)_6$,is an octahedral compound involving which type of hybridization?

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