Which of the following complex ions has a mag | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The spin-only magnetic moment $(\mu)$ is given by the formula $\mu = \sqrt{n(n 2)} \ BM$,where $n$ is the number of unpaired electrons.For $[Cr(H_

Vedclass · Accepted Answer

$[Mn(H_2O)_6]^{4+}$

Vedclass · Answer

(A) The spin-only magnetic moment $(\mu)$ is given by the formula $\mu = \sqrt{n(n 2)} \ BM$,where $n$ is the number of unpaired electrons.For $[Cr(H_2O)_6]^{3 }$,the oxidation state of $Cr$ is $ 3$. The electronic configuration of $Cr^{3 }$ is $[Ar]3d^3$,which has $n = 3$ unpaired electrons.For $[Mn(H_2O)_6]^{4 }$,the oxidation state of $Mn$ is $ 4$. The electronic configuration of $Mn^{4 }$ is $[Ar]3d^3$,which has $n = 3$ unpaired electrons.For $[Mn(H_2O)_6]^{3 }$,the oxidation state of $Mn$ is $ 3$. The electronic configuration of $Mn^{3 }$ is $[Ar]3d^4$,which has $n = 4$ unpaired electrons.For $[Fe(H_2O)_6]^{3 }$,the oxidation state of $Fe$ is $ 3$. The electronic configuration of $Fe^{3 }$ is $[Ar]3d^5$,which has $n = 5$ unpaired electrons.For $[Cu(NH_3)_4]^{2 }$,the oxidation state of $Cu$ is $ 2$. The electronic configuration of $Cu^{2 }$ is $[Ar]3d^9$,which has $n = 1$ unpaired electron.Since $[Cr(H_2O)_6]^{3 }$ and $[Mn(H_2O)_6]^{4 }$ both have $n = 3$,they have the same magnetic moment.

Which of the following complex ions has a magnetic moment same as $[Cr(H_2O)_6]^{3+}$?

Similar Questions

Which of the following is not correctly matched?

Geometric isomerism is exhibited by which of the following coordination compounds?

Which of the following aquated metal ions has the highest paramagnetism?

The number of geometric isomers for the complex $[Co(NO_2)_2(NH_3)_2]$ is .....

Vedclass Test Series

Exam Paper Generator

Online Exam Module