The [Sc(H_2O)_6]^{3+} ion is: | vedclass

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(A) The electronic configuration of neutral scandium is $_{21}Sc = [Ar] \; 3d^1 4s^2$. For the $Sc^{3+}$ ion,three electrons are removed,resulting in

Vedclass · Accepted Answer

Colourless and diamagnetic

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(A) The electronic configuration of neutral scandium is $_{21}Sc = [Ar] \; 3d^1 4s^2$. For the $Sc^{3+}$ ion,three electrons are removed,resulting in the configuration $Sc^{3+} = [Ar] \; 3d^0 4s^0$. Since there are no unpaired electrons in the $d$-subshell,the ion does not undergo $d-d$ transitions and is therefore colourless. Additionally,the absence of unpaired electrons makes it diamagnetic.

The $[Sc(H_2O)_6]^{3+}$ ion is:

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