Which of the following aqueous solutions will | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The elevation in boiling point is given by the formula $\Delta T_b = i 	imes K_b 	imes m$. Since $K_b$ is constant for the solvent,$\Delta T_b$

Vedclass · Accepted Answer

$0.01 \ M \ Na_2SO_4$

Vedclass · Answer

(A) The elevation in boiling point is given by the formula $\Delta T_b = i 	imes K_b 	imes m$. Since $K_b$ is constant for the solvent,$\Delta T_b$ depends on the product of the van't Hoff factor $(i)$ and molality $(m)$. For $0.01 \ M \ Na_2SO_4$,$i = 3$ (as it dissociates into $2Na^+ + SO_4^{2-}$),so $i 	imes m = 3 	imes 0.01 = 0.03$. For $0.01 \ M \ KNO_3$,$i = 2$ (as it dissociates into $K^+ + NO_3^-$),so $i 	imes m = 2 	imes 0.01 = 0.02$. For $0.015 \ M$ urea,$i = 1$ (non-electrolyte),so $i 	imes m = 1 	imes 0.015 = 0.015$. For $0.015 \ M$ glucose,$i = 1$ (non-electrolyte),so $i 	imes m = 1 	imes 0.015 = 0.015$. Since $0.01 \ M \ Na_2SO_4$ has the highest value of $i 	imes m$,it will exhibit the highest boiling point.

Which of the following aqueous solutions will exhibit the highest boiling point?

Similar Questions

$A$ solution of a nonvolatile solute is obtained by dissolving $1.5 \ g$ in $30 \ g$ of solvent. The boiling point elevation is $0.65 \ K$. Calculate the molal elevation constant if the molar mass of the solute is $150 \ g \ mol^{-1}$.

The molal boiling point constant for water is $0.513 \, ^oC \, kg \, mol^{-1}$. When $0.1 \, mol$ of sugar is dissolved in $200 \, mL$ of water,the solution boils under a pressure of one atmosphere at ......... $^oC$.

When a substance is dissolved in a solvent,the vapour pressure of the solvent is decreased. This results in:

The following graph shows the vapour pressure (in $atm$) on the $y$-axis versus temperature $T$ (in $K$) on the $x$-axis for pure water and an aqueous urea solution. What is the boiling point (in $K$) of the urea solution? (Atmospheric pressure $= 1 \ atm$)

The boiling point of toluene is $110.7\,^oC$ and its molal elevation constant is $3.32\, K\, kg\, mol^{-1}$. The enthalpy of vaporization of liquid toluene is ............ $kJ\, mol^{-1}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module