Which of the following 0.10 m aqueous soluti | vedclass

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Question

(A) The depression in freezing point is given by the formula $\Delta T_{f} = i 	imes K_{f} 	imes m$. Since $K_{f}$ and $m$ $(0.10 \ m)$ are constant

Vedclass · Accepted Answer

$Al_{2}(SO_{4})_{3}$

Vedclass · Answer

(A) The depression in freezing point is given by the formula $\Delta T_{f} = i 	imes K_{f} 	imes m$. Since $K_{f}$ and $m$ $(0.10 \ m)$ are constant for all solutions,$\Delta T_{f}$ depends directly on the van't Hoff factor $(i)$. $i$ represents the number of particles produced upon dissociation. For $Al_{2}(SO_{4})_{3}$,$i = 5$ $(2Al^{3+} + 3SO_{4}^{2-})$. For $KI$,$i = 2$ $(K^{+} + I^{-})$. For $C_{12}H_{22}O_{11}$ (sucrose) and $NH_{2}CONH_{2}$ (urea),$i = 1$ as they are non-electrolytes. Since $Al_{2}(SO_{4})_{3}$ has the highest $i$ value,it will have the maximum $\Delta T_{f}$ value.

Which of the following $0.10 \ m$ aqueous solutions will have the maximum $\Delta T_{f}$ value?

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