Which of the configuration is correct :-
$CO : \sigma ls^2 ..... \sigma 2pz^2, \pi 2py^2$
$CN^-: \sigma 1s^2 ..... \sigma 2pz^2, \pi 2px^2$
$NO : \sigma 1s^2 ..... \pi^*2px^1, \pi^*2py^0$
$N_2^+ : \sigma 1s^2 ..... \sigma 2pz^2, \pi 2py^1$
Consider the ions/molecule
$O _{2}^{+}, O _{2}, O _{2}^{-}, O _{2}^{2-}$
For increasing bond order the correct option is ..... .
Bond energies in $NO,\,N{O^ + }$ and $N{O^ - }$ are such as
According to $MO$ theory, number of species/ions from the following having identical bond order is $.........$
$CN ^{-}, NO ^{+}, O _{2}, O _{2}^{+}, O _{2}^{2+}$
The correct order of bound orders of $C _{2}^{2-}, N _{2}^{2-}$ and $O _{2}^{2-}$ is, respectively.
For $F_2$ and $OF$ molecules consider the following statements
$(a)$ Bond order for both is one
$(b)$ $OF$ is paramagnetic but $F_2$ is diamagnetic
$(c)$ $F_2$ is more likely to dissociate into atoms than $OF$
$(d)$ Both have greater number of electrons in $BMO$ than that in $ABMO$
Which of the following statements are true $(T)$ or false $(F)$ respectively