The correct order of bound orders of $C _{2}^{2-}, N _{2}^{2-}$ and $O _{2}^{2-}$ is, respectively.

  • [JEE MAIN 2022]
  • A

    $C _{2}^{2-}< N _{2}^{2-}< O _{2}^{2-}$

  • B

    $O _{2}^{2-}< N _{2}^{2-}< C _{2}^{2-}$

  • C

    $C _{2}^{2-}< O _{2}^{2-}< N _{2}^{2-}$

  • D

    $N _{2}^{2-}< C _{2}^{2-}< O _{2}^{2-}$

Similar Questions

Which of the following statement is correct for peroxide ion

$A.$  has completely filled $\pi$ antibonding molecular orbitals
$B.$  is diamagnetic
$C.$  has bond order one
$D.$  is isoelectronic with Neon

The total number of electron that takes part in forming bonds in ${N_2}$ is

Which of the following species show maximum bond length ?

Calculate the bond order of ${{\rm{N}}_2},{{\rm{O}}_2}{\rm{,O}}_2^ + $ and ${\rm{O}}_2^ - $

Assertion :Fluorine molecule has bond order one.
Reason : The number of electrons in the antibonding molecular orbitals is two less than that in bonding molecular orbitals.

  • [AIIMS 2008]