The correct order of bound orders of $C _{2}^{2-}, N _{2}^{2-}$ and $O _{2}^{2-}$ is, respectively.
$C _{2}^{2-}< N _{2}^{2-}< O _{2}^{2-}$
$O _{2}^{2-}< N _{2}^{2-}< C _{2}^{2-}$
$C _{2}^{2-}< O _{2}^{2-}< N _{2}^{2-}$
$N _{2}^{2-}< C _{2}^{2-}< O _{2}^{2-}$
Which of the following statement is correct for peroxide ion
$A.$ has completely filled $\pi$ antibonding molecular orbitals
$B.$ is diamagnetic
$C.$ has bond order one
$D.$ is isoelectronic with Neon
The total number of electron that takes part in forming bonds in ${N_2}$ is
Which of the following species show maximum bond length ?
Calculate the bond order of ${{\rm{N}}_2},{{\rm{O}}_2}{\rm{,O}}_2^ + $ and ${\rm{O}}_2^ - $
Assertion :Fluorine molecule has bond order one.
Reason : The number of electrons in the antibonding molecular orbitals is two less than that in bonding molecular orbitals.