Which is the correct relationship between wavelength and momentum of particles?

  • A
    $\lambda = \frac{h}{p}$
  • B
    $\pi = \frac{h}{p}$
  • C
    $p = \frac{h}{\lambda}$
  • D
    $h = \frac{p}{\lambda}$

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The de Broglie wavelength of an electron travelling with $20 \%$ of velocity of light is
$(h = 6.626 \times 10^{-34} \ J \ s; m_{e} = 9.1 \times 10^{-31} \ kg)$

Write about the dual behaviour of matter.

The de Broglie wavelength $(\lambda)$ associated with a photoelectron varies with the frequency $(v)$ of the incident radiation as,[$v_0$ is threshold frequency]:

If $v_0$ is the threshold frequency of a metal $X$,the correct relation between de Broglie wavelength $(\lambda)$ associated with the photoelectron and the frequency $(v)$ of the incident radiation is:

If the wavelength of a photon is $2.2 \times 10^{-11} \ m$ and $h = 6.6 \times 10^{-34} \ J \ s$,then the momentum of the photon is:

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