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(B) The velocity of light $c = 3 	imes 10^8 \ m \ s^{-1}$. The velocity of the electron $v = 20 \% 	ext{ of } c = \frac{20}{100} 	imes 3 	imes 10^

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$1.2 	imes 10^{-11} \ m$

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(B) The velocity of light $c = 3 	imes 10^8 \ m \ s^{-1}$. The velocity of the electron $v = 20 \% 	ext{ of } c = \frac{20}{100} 	imes 3 	imes 10^8 \ m \ s^{-1} = 6 	imes 10^7 \ m \ s^{-1}$. The de Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{m_{e} v}$. Substituting the values: $\lambda = \frac{6.626 	imes 10^{-34} \ J \ s}{(9.1 	imes 10^{-31} \ kg) 	imes (6 	imes 10^7 \ m \ s^{-1})}$. $\lambda = \frac{6.626 	imes 10^{-34}}{54.6 	imes 10^{-24}} \ m \approx 0.1213 	imes 10^{-10} \ m = 1.213 	imes 10^{-11} \ m$. Thus,the correct option is $B$.

The de Broglie wavelength of an electron travelling with $20 \%$ of velocity of light is
$(h = 6.626 \times 10^{-34} \ J \ s; m_{e} = 9.1 \times 10^{-31} \ kg)$

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The de Broglie wavelength of an electron travelling with $20 \%$ of velocity of light is $(h = 6.626 \times 10^{-34} \ J \ s; m_{e} = 9.1 \times 10^{-31} \ kg)$