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(C) To determine the number of non-planar species,we analyze the geometry of each:$1$. $NO_{3}^{-}$: $sp^{2}$ hybridization,trigonal planar.$2$. $H_{2

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$6$

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(C) To determine the number of non-planar species,we analyze the geometry of each:$1$. $NO_{3}^{-}$: $sp^{2}$ hybridization,trigonal planar.$2$. $H_{2}O_{2}$: Open book structure,non-planar.$3$. $BF_{3}$: $sp^{2}$ hybridization,trigonal planar.$4$. $PCl_{3}$: $sp^{3}$ hybridization,trigonal pyramidal,non-planar.$5$. $XeF_{4}$: $sp^{3}d^{2}$ hybridization,square planar.$6$. $SF_{4}$: $sp^{3}d$ hybridization,see-saw shape,non-planar.$7$. $XeO_{3}$: $sp^{3}$ hybridization,trigonal pyramidal,non-planar.$8$. $PH_{4}^{+}$: $sp^{3}$ hybridization,tetrahedral,non-planar.$9$. $SO_{3}$: $sp^{2}$ hybridization,trigonal planar.$10$. $[Al(OH)_{4}]^{-}$: $sp^{3}$ hybridization,tetrahedral,non-planar.The non-planar species are: $H_{2}O_{2}, PCl_{3}, SF_{4}, XeO_{3}, PH_{4}^{+}, [Al(OH)_{4}]^{-}$.Counting these,we get a total of $6$ non-planar species.

The number of molecule$(s)$ or ion$(s)$ from the following having non-planar structure is
$NO_{3}^{-}, H_{2}O_{2}, BF_{3}, PCl_{3}, XeF_{4}, SF_{4}, XeO_{3}, PH_{4}^{+}, SO_{3}, [Al(OH)_{4}]^{-}$

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The number of molecule$(s)$ or ion$(s)$ from the following having non-planar structure is$NO_{3}^{-}, H_{2}O_{2}, BF_{3}, PCl_{3}, XeF_{4}, SF_{4}, XeO_{3}, PH_{4}^{+}, SO_{3}, [Al(OH)_{4}]^{-}$