Which is most reactive for SN^2 reaction? | vedclass

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Question

(C) The reactivity of alkyl halides towards $SN^2$ reaction follows the order: $Primary > Secondary > Tertiary$ due to steric hindrance.Additionally,f

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$CH_3CH_2Br$

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(C) The reactivity of alkyl halides towards $SN^2$ reaction follows the order: $Primary > Secondary > Tertiary$ due to steric hindrance.Additionally,for the same alkyl group,the leaving group ability follows the order: $I^- > Br^- > Cl^- > F^-$.Comparing the given options:$(A)$ $CH_3CH_2CH_2CH_2Cl$ is a primary alkyl chloride.$(B)$ $CH_3CH(Cl)CH_3$ is a secondary alkyl chloride.$(C)$ $CH_3CH_2Br$ is a primary alkyl bromide.$(D)$ $(CH_3)_2CHCH_2Cl$ is a primary alkyl chloride with branching at the $\beta$-carbon.Between primary alkyl halides,$CH_3CH_2Br$ $(C)$ is more reactive than $CH_3CH_2CH_2CH_2Cl$ $(A)$ because $Br^-$ is a better leaving group than $Cl^-$. Therefore,$CH_3CH_2Br$ is the most reactive towards $SN^2$ reaction.

Which is most reactive for $SN^2$ reaction?

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