What is the major product Z in the given reac | vedclass

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(D) Step $1$: Reaction of acetone with $C_2H_5MgBr$ followed by hydrolysis gives $2-$methylbutan$-2-$ol $(X)$: $(CH_3)_2C=O + C_2H_5MgBr \rightarrow (

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$1-$Bromo$-2-$methylbutane

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(D) Step $1$: Reaction of acetone with $C_2H_5MgBr$ followed by hydrolysis gives $2-$methylbutan$-2-$ol $(X)$: $(CH_3)_2C=O + C_2H_5MgBr \rightarrow (CH_3)_2C(OH)C_2H_5$.Step $2$: Reaction of $X$ with $SOCl_2$ gives $2-$chloro$-2-$methylbutane,which upon treatment with $CH_3ONa$ (base) undergoes dehydrohalogenation to form $2-$methylbut$-2-$ene $(Y)$ as the major product.Step $3$: Addition of $HBr$ to $2-$methylbut$-2-$ene in the presence of peroxide follows anti-Markovnikov's rule to give $1-$bromo$-2-$methylbutane $(Z)$.

What is the major product $Z$ in the given reaction sequence?
$(CH_3)_2 C=O \xrightarrow[(2) H_3O^{+}]{\text{(1) } C_2H_5MgBr} X$
$i) SOCl_2$ $\xrightarrow[\Delta]{\text{ii) } CH_3ONa} Y$ $\xrightarrow[\text{Peroxide}]{HBr} Z$

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What is the major product $Z$ in the given reaction sequence?$(CH_3)_2 C=O \xrightarrow[(2) H_3O^{+}]{\text{(1) } C_2H_5MgBr} X$$i) SOCl_2$ $\xrightarrow[\Delta]{\text{ii) } CH_3ONa} Y$ $\xrightarrow[\text{Peroxide}]{HBr} Z$