Which intermediate is formed in the Reimer-Ti | vedclass

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Question

(D) In the Reimer-Tiemann reaction,phenol is treated with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaOH)$.This reaction pro

Vedclass · Accepted Answer

Substituted benzal chloride

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(D) In the Reimer-Tiemann reaction,phenol is treated with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaOH)$.This reaction proceeds via the formation of a dichlorocarbene $(:CCl_2)$ intermediate,which attacks the phenoxide ion to form a substituted benzal chloride intermediate.This intermediate is subsequently hydrolyzed to form salicylaldehyde.Therefore,the intermediate formed is a substituted benzal chloride.

Which intermediate is formed in the Reimer-Tiemann reaction?

Similar Questions

Phenol $\xrightarrow{Zn \, \text{dust}} X$ $\xrightarrow[Anhyd. \, AlCl_3]{CH_3Cl} Y$ $\xrightarrow{\text{Alkaline } KMnO_4} Z$. In the above reaction,what is $Z$?

Describe the electrophilic aromatic substitution reactions of phenol.

The reaction sequence is as follows:
$Catechol \xrightarrow{(i) CHCl_3 + KOH}{(ii) CH_2I_2 + NaOH} [X]$
Here $[X]$ is:

Which one of the following properties is exhibited by phenol?

The major product of the following reaction is:

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