Which compound is optically active

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Question

(c) $\mathop {C{H_3} - \mathop {\mathop {\mathop {C\,\,\, - }\limits_{|\,\,\,\,\,\,\,}^{|\,\,\,\,\,} }\limits^{H\,\,} }\limits_{\,N{H_2}} C{H_2} - C{H

Vedclass · Accepted Answer

Secondary butyl amine

Vedclass · Answer

(c) $\mathop {C{H_3} - \mathop {\mathop {\mathop {C\,\,\, - }\limits_{|\,\,\,\,\,\,\,}^{|\,\,\,\,\,} }\limits^{H\,\,} }\limits_{\,N{H_2}} C{H_2} - C{H_3}}\limits_{} $

Secondary butyl amine is optically active.

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