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(C) Mono-chlorination involves the replacement of a hydrogen atom with a chlorine atom in the presence of light $(h
u)$.For a compound to yield only

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neo-pentane

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(C) Mono-chlorination involves the replacement of a hydrogen atom with a chlorine atom in the presence of light $(h
u)$.For a compound to yield only one mono-chlorination product,all hydrogen atoms in the molecule must be equivalent.$A$. $n-$Butane $(CH_3-CH_2-CH_2-CH_3)$ has two types of hydrogen atoms,yielding two products.$B$. iso-pentane $((CH_3)_2CH-CH_2-CH_3)$ has four types of hydrogen atoms,yielding four products.$C$. neo-pentane $((CH_3)_4C)$ has all $12$ hydrogen atoms equivalent (attached to the same type of carbon),yielding only one product: $1-$chloro-$2,2-$dimethylpropane.$D$. $n-$pentane $(CH_3-CH_2-CH_2-CH_2-CH_3)$ has three types of hydrogen atoms,yielding three products.Therefore,the correct answer is $C$.

Which compound in the following will give only one mono-chlorination product in the presence of light?

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