Which among the following is most paramagneti | vedclass

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(B) Paramagnetic character depends on the number of unpaired electrons in the $d$-subshell.In these complex ions,$H_2O$ is a weak field ligand,so the

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$[Fe(H_2O)_6]^{2+}$

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(B) Paramagnetic character depends on the number of unpaired electrons in the $d$-subshell.In these complex ions,$H_2O$ is a weak field ligand,so the electrons remain unpaired according to Hund's rule:$(a)$ In $[Cr(H_2O)_6]^{3+}$,$Cr^{3+}$ has a $3d^3$ configuration. Number of unpaired electrons $= 3$.$(b)$ In $[Fe(H_2O)_6]^{2+}$,$Fe^{2+}$ has a $3d^6$ configuration. In an octahedral field,this corresponds to $t_{2g}^4 e_g^2$,resulting in $4$ unpaired electrons.$(c)$ In $[Cu(H_2O)_6]^{2+}$,$Cu^{2+}$ has a $3d^9$ configuration. Number of unpaired electrons $= 1$.$(d)$ In $[Zn(H_2O)_6]^{2+}$,$Zn^{2+}$ has a $3d^{10}$ configuration. Number of unpaired electrons $= 0$.Since paramagnetic character is directly proportional to the number of unpaired electrons,$[Fe(H_2O)_6]^{2+}$ is the most paramagnetic.

Which among the following is most paramagnetic?

Similar Questions

Which of the following statements is not true about the complex ion $[Cr(en)_2Cl_2]^+$?

The pair$(s)$ of coordination complexes/ions exhibiting the same kind of isomerism is(are)
$(A)$ $[Cr(NH_3)_5Cl]Cl_2$ and $[Cr(NH_3)_4Cl_2]Cl$
$(B)$ $[Co(NH_3)_4Cl_2]^+$ and $[Pt(NH_3)_2(H_2O)Cl]^+$
$(C)$ $[CoBr_2Cl_2]^{2-}$ and $[PtBr_2Cl_2]^{2-}$
$(D)$ $[Pt(NH_3)_3(NO_3)]Cl$ and $[Pt(NH_3)_3Cl]Br$

The increasing order of magnetic moments for the following complexes is:
$I$. $[Fe(CN)_6]^{4-}$
$II$. $[Fe(CN)_6]^{3-}$
$III$. $[Cr(NH_3)_6]^{3+}$
$IV$. $[Ni(H_2O)_4]^{2+}$

Identify the complex ion with spin only magnetic moment of $4.90 \ BM$.

Among the following,the pair of paramagnetic complexes is

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