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(C) In the electrolysis of brine solution ($NaCl$ aqueous),the solution contains $Na^{+}$,$Cl^{-}$,$H^{+}$,and $OH^{-}$ ions.At the cathode,$H^{+}$ io

Vedclass · Accepted Answer

$H_2$ gas is liberated at cathode

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(C) In the electrolysis of brine solution ($NaCl$ aqueous),the solution contains $Na^{+}$,$Cl^{-}$,$H^{+}$,and $OH^{-}$ ions.At the cathode,$H^{+}$ ions (from water) have a higher reduction potential than $Na^{+}$ ions,so $H_2$ gas is liberated.Reaction at cathode: $2H_2O(l) + 2e^{-} \rightarrow H_2(g) + 2OH^{-}(aq)$.At the anode,$Cl^{-}$ ions are oxidized to $Cl_2$ gas.Reaction at anode: $2Cl^{-}(aq) \rightarrow Cl_2(g) + 2e^{-}$.Therefore,$H_2$ gas is liberated at the cathode.

Which among the following is correct for the electrolysis of brine solution?

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