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(C) The kinetic energy $(KE)$ of a body is given by the formula: $KE = \frac{1}{2} m v^2$,where $m$ is the mass and $v$ is the speed.Let the initial m

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becomes eight times

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(C) The kinetic energy $(KE)$ of a body is given by the formula: $KE = \frac{1}{2} m v^2$,where $m$ is the mass and $v$ is the speed.Let the initial mass be $m$ and the initial speed be $v$. Then the initial kinetic energy is $KE_i = \frac{1}{2} m v^2$.According to the problem,the mass is doubled $(m' = 2m)$ and the speed is doubled $(v' = 2v)$.The final kinetic energy $KE_f$ is given by:$KE_f = \frac{1}{2} (2m) (2v)^2$$KE_f = \frac{1}{2} (2m) (4v^2)$$KE_f = 8 	imes (\frac{1}{2} m v^2)$$KE_f = 8 KE_i$Therefore,the kinetic energy becomes eight times the initial kinetic energy.

When the mass and speed of the body are doubled,the kinetic energy of the body

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