When propionic acid is treated with aqueous s | vedclass

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Question

(D) The reaction between propionic acid and sodium bicarbonate is an acid-base reaction: $CH_3CH_2COOH_{(aq)} + NaHCO_{3(aq)} 	o CH_3CH_2COONa_{(aq)}

Vedclass · Accepted Answer

Bicarbonate

Vedclass · Answer

(D) The reaction between propionic acid and sodium bicarbonate is an acid-base reaction: $CH_3CH_2COOH_{(aq)} + NaHCO_{3(aq)} 	o CH_3CH_2COONa_{(aq)} + H_2O_{(l)} + CO_{2(g)}$ In this reaction,the carboxylic acid $(R-COOH)$ acts as a proton donor,and the bicarbonate ion $(HCO_3^-)$ acts as a base. The $HCO_3^-$ ion accepts a proton to form carbonic acid $(H_2CO_3)$,which then decomposes into $H_2O$ and $CO_2$. Therefore,the carbon atom in the evolved $CO_2$ gas originates from the bicarbonate ion $(NaHCO_3)$. Thus,the correct option is $(D)$.

When propionic acid is treated with aqueous sodium bicarbonate,$CO_2$ is liberated. The '$C$' of $CO_2$ comes from:

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