Identify the product of the Fischer esterific | vedclass

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(C) The reaction shown is a Fischer esterification,where a carboxylic acid reacts with an alcohol in the presence of an acid catalyst (like $HCl$) to

Vedclass · Accepted Answer

$Ph-CH(OH)-CO_2Et$

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(C) The reaction shown is a Fischer esterification,where a carboxylic acid reacts with an alcohol in the presence of an acid catalyst (like $HCl$) to form an ester and water. In this reaction,Mandelic acid $(Ph-CH(OH)-COOH)$ reacts with ethanol $(EtOH)$ in the presence of $HCl$. The carboxylic acid group $(-COOH)$ is converted into an ester group $(-COOEt)$,while the hydroxyl group $(-OH)$ attached to the alpha-carbon remains unaffected under these specific conditions. The reaction is: $Ph-CH(OH)-COOH + C_2H_5OH \xrightarrow{HCl} Ph-CH(OH)-COOC_2H_5 + H_2O$ Thus,the product is ethyl mandelate,which corresponds to option $C$.

Identify the product of the Fischer esterification reaction shown below:

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